Why is Starter used for starting Dc motor?
At the time of starting of motor , the speed of the motor is zero hence the back emf ( or induced emf) across the armature is zero ( since , Eb directly proportional N). So the motor will draw a very large current due to a very small armature resistance when it is connected to related supply voltage .
Let us consider a 400 D.C Shunt motor with full load current of 50A and armature resistance of 0.2 ohms . At the time of starting , This motor will draw V / Ra = 400 / 0.2 = 2000A , which is 40 times that of full load current of motor. Similarly , a 220V series motor with full load current of 20A and armature and series field resistance of 0.3 ohms and 0.2 ohms respectively will draw.
V(Ra + Rf ) = 220 / (0.3 + 0.2) = 440A
Which is 22 times of the full load current . This excessive current will cause
- the burning of armature winding
- reduction of life period of armature due to mechanical shock with large sudden torque
- Damage of commutator and brush gear due to heavy sparking
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