INTRODUCTION
The branch of electronics , which deals with digital circuits, it called digital electronics . the term digital reminds up of digital products can be attributed to low cost , good performance and rapid innovation in the field in the last few decades . Digital techniques have also replaced lots of older "Analog Circuit" used in consumer products such as, radio , T.V , etc.
Note
In this series we read basic to Advance of Digital Electronics
BINARY NUMBER SYSTEM
A number system is a code that used symbols to count numbers . The most common and familiar number system is "Decimal number system" The decimal number system used the symbol is 0 , 1 , 2 , 3 , 4 , 5 ,6 , 7 , 8 and 9 . Thus the decimal system used 10 digits for counting . A binary system used only two Digits 0 and 1 only .
For example : 1001 , 111 , 0001 , all are binary number
Every number system has placed value for every number
For example : 482 in a decimal system is represented as - 4 × 10^2 + 8 × 10^1 + 2 × 10^0
In similar way , a binary number also has a placed value for each digit .
CONVERSION OF BINARY NUMBER INTO DECIMAL NUMBER
To convert a binary number into its decimal equivalent some instruction are given below
1. Read the binary number from right to left and multiply each binary number 2⁰ , 2¹ , 2² , 2³ , 2⁴ , 2⁵ , 2⁶ and so on
2. Add individual number . This will be decimal equivalent of the number .
Now we practice some Question Based On Decimal Number
Q1. Convert the Binary number ( 1101011 ) 2 into its decimal equation .
Solution - Read number Right to left and multiplying digits with increasing power of 2 , we found
1 × 2⁶ + 1 × 2⁵ + 0 × 2⁴ + 1 × 2³ + 0 × 2² + 1 × 2¹ + 1 × 2⁰
= 64 + 32 + 0 + 8 + 0 + 2 + 1
= 107
Q2. convert ( 1101.11 )2 into decimal equivalent
Solution - we can solute into two part of this question
(1101.12)2 = ( 1 × 2³ + 1 × 2² + 0 × 2¹ + 1 × 2⁰ ) + ( 1 × 2-¹ + 1 × 2-²)
= ( 8 + 4 + 0 + 1 ) + ( 0.5 + 0.25 )
= 13.75
Note
If binary number is in decimal , then , read from left to right and multiplying by (-ve power) show above question
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